(2x-1)(3x^2+2x-4)=

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Solution for (2x-1)(3x^2+2x-4)= equation: 


Simplifying
(2x + -1)(3x2 + 2x + -4) = 0

Reorder the terms:
(-1 + 2x)(3x2 + 2x + -4) = 0

Reorder the terms:
(-1 + 2x)(-4 + 2x + 3x2) = 0

Multiply (-1 + 2x) * (-4 + 2x + 3x2)
(-1(-4 + 2x + 3x2) + 2x * (-4 + 2x + 3x2)) = 0
((-4 * -1 + 2x * -1 + 3x2 * -1) + 2x * (-4 + 2x + 3x2)) = 0
((4 + -2x + -3x2) + 2x * (-4 + 2x + 3x2)) = 0
(4 + -2x + -3x2 + (-4 * 2x + 2x * 2x + 3x2 * 2x)) = 0
(4 + -2x + -3x2 + (-8x + 4x2 + 6x3)) = 0

Reorder the terms:
(4 + -2x + -8x + -3x2 + 4x2 + 6x3) = 0

Combine like terms: -2x + -8x = -10x
(4 + -10x + -3x2 + 4x2 + 6x3) = 0

Combine like terms: -3x2 + 4x2 = 1x2
(4 + -10x + 1x2 + 6x3) = 0

Solving
4 + -10x + 1x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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